Question

Solve the given in exponential equation 2^2x+1=4^2x-1

Answer 1

$\textbf{Given:}$

$\mathsf{2^{2x+1}=4^{2x-1}}$

$\textbf{To find:}$

$\textsf{Solution of the given equation}$

$\textbf{Solution:}$

$\mathsf{Consider,}$

$\mathsf{2^{2x+1}=4^{2x-1}}$

$\mathsf{2^{2x+1}=(2^2)^{2x-1}}$

$\mathsf{2^{2x+1}=2^{2(2x-1)}}$

$\mathsf{2^{2x+1}=2^{4x-2}}$

$\textsf{Equating powers on bothsides, we get}$

$\mathsf{2x+1=4x-2}$

$\mathsf{2x-4x=-2-1}$

$\mathsf{-2x=-3}$

$\mathsf{2x=3}$

$\implies\boxed{\mathsf{x=\dfrac{3}{2}}}$

$\textbf{Find more:}$

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Answer 2

Step-by-step explanation:

here's your answer bro