Solve the given linear equations by the elimination method:. 6x+2y-3=0. x+4y+1=0
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Answered by
1
6x+2y=3.......¡×1
x+4y=-1.........¡¡×6
6x+2y=3........¡¡¡
6x+24y=-6.....¡v
-22y=9
=>y=9/-22
Putting y=9/-22 in. ¡¡¡ we get
6x+2y=3
=>6x+2(9/-22)=3
=>6x+(9/-11)=3
=>66x+9/-11=3
=>66x+9=-33
=>66x=42
=>x=42/66
x+4y=-1.........¡¡×6
6x+2y=3........¡¡¡
6x+24y=-6.....¡v
-22y=9
=>y=9/-22
Putting y=9/-22 in. ¡¡¡ we get
6x+2y=3
=>6x+2(9/-22)=3
=>6x+(9/-11)=3
=>66x+9/-11=3
=>66x+9=-33
=>66x=42
=>x=42/66
Answered by
0
6x + 2y = 3 ------------ (1)
x + 4y = -1 --------------(2)
we multiply equation 2 from (6) we get
NOW SUBTRACT EQUATION 1 FROM 2 WE GET
6x + 24y = -6
6x + 2y = 3
----------------------
0 + 22y = -9
y = -9/22
NOW PUT THE VALUE OF Y IN EQUATION (2) WE GET
x = 4*-9/22 -1
= -36/22 - 1
= -52/22
PLZ MARK AS BRAINLIST
x + 4y = -1 --------------(2)
we multiply equation 2 from (6) we get
NOW SUBTRACT EQUATION 1 FROM 2 WE GET
6x + 24y = -6
6x + 2y = 3
----------------------
0 + 22y = -9
y = -9/22
NOW PUT THE VALUE OF Y IN EQUATION (2) WE GET
x = 4*-9/22 -1
= -36/22 - 1
= -52/22
PLZ MARK AS BRAINLIST
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