Question

Solve the given linear pair of equations by substitution method.
x+y=5 and 2x-3y=4​

Answer 1

x + y = 5 and 2x – 3y = 4

SOLUTION

x + y =5 and 2x –3y = 4

By elimination method

x + y =5 ... (i)

2x –3y = 4 ... (ii)

Multiplying equation (i) by (ii), we get

2x + 2y = 10 ... (iii)

2x –3y = 4 ... (ii)

Subtracting equation (ii) from equation (iii), we get

5y = 6

y = 6/5

Putting the value in equation (i), we get

x = 5 - (6/5) = 19/5

Hence, x = 19/5 and y = 6/5

By substitution method

x + y = 5 ... (i)

Subtracting y both side, we get

x = 5 - y ... (iv)

Putting the value of x in equation (ii) we get

2(5 – y) – 3y = 4

-5y = - 6

y = -6/-5 = 6/5

Putting the value of y in equation (iv) we get

x = 5 – 6/5

x = 19/5

Hence, x = 19/5 and y = 6/5 again

Answer 2

Answer:

x+y=5 and 2x−3y=4

x+y=5.(i)

2x−3y=4.(ii)

Multiplying eqn (i) by 3

3x+3y=15.(iii)

By adding (ii) to (iii) , 'y' is eliminated .

5x=19

x= 19/5

since x+y=5

19/5 +y=5

y= 5/1 − 19/5

= 25−19 /5

y= 6/5

Step-by-step explanation:

hope it helps