Question

solve the given pair of linear equation
$(a - b)x + (a + b)y = a ^{2} - 2ab - b ^{2} \\ (a + b)(x + y) = a ^{2} + b ^{2}$
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Answer 1

=> (a-b) x + (a + b) y = a² - 2ab - b²…………(1)

=> (a + b) (x + y) = a² + b²……………………(2)

=> Equation (2) can be written as (a + b)x+ => (a+b) y = a² + b²………….(3)

=> Now we have to solve equation (1) and (3)

=> (a-b) x + (a + b) y = a² - 2ab - b²,…………(1)

=> (a + b)x+ (a+b) y = a² + b²………….(3)

=> Subtracting equation (3) from (1) we get

=> (a-b-a-b) x = a² - 2ab - b²- a² - b²

=> -2b x = - 2ab -2 b²

=> -2b x =-2b(a+b)

=> dividing both sides by -2b

= x = a+b

=> Now substitude x=a+b in equation (1) we get

=> (a-b)(a+b) + (a + b) y = a² - 2ab - b²

=> a² - b² + + (a + b) y = a² - 2ab - b²

=> Subtracting a² - b² from both the sides

=> (a + b) y = a² - 2ab - b² - a² + b²

=> (a + b) y = - 2ab

=> y = - 2ab /(a+b)

=>Answer x = a+b , y = - 2ab /(a+b)

I hope this will help you dear..

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Answer 2

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$\large \bold \color{green}{hi \: \: i \: actuall \: solved \: it \: so \: here \: is \: attachment \: }$

hope it helps you

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