Question

Solve the given pair of linear equations:
2x +3y =6
x +y = 8​

Answer 1

Answer:

Step-by-step explanation:

2x + 3y = 6 .....(i)

x + y = 8......(ii)

multiplying equation (ii) with 2 and subtract both the equation

2x + 3y = 6

2x + 2y = 16

- - -

y = -10

now from equation (ii)

x+ (-10) =8

x -10 =8

x =8+10

x =18

hence x= 18 & y =-10

Answer 2

Answer:

2x+ 3y =6

as x+y =8

we can try trail and error method

hear we need one positive integer and one negetive so

lets take out pairs

x,y

15,-7 =8

16,-8=8

17,-9=8

18,-10=8

we will take 18,-10 = 8

2(18) + 3(-10)=6

36+ (-30) = 6

therefore x = 18 and y= -10

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