Math, asked by manjindersra0981, 5 months ago

Solve the given pair of linear equations:
2x +3y =6
x +y = 8​

Answers

Answered by swati2010
0

Answer:

x=18 and y= -10

multiply 2 in equation second.

then ,2x+3y= 6

- 2x+2y= 16

y = - 10

x+ y = 8

x + (-10)=8

x = 18 (ans)

Step-by-step explanation:

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Answered by roshankaran871
0

Answer:

Answer:(18,-10)

Step-by-step explanation:

Given,

2x + 3y = 6 \\ x + y = 8  \\ 2x + 3y = 6 \\x = 8 - y \\ substitute \: the \: value \: of \: x \\ 2(8 - y) + 3y = 6 \\  = y =  - 10 \\ therefore  \: x = 8 - ( - 10) \\  = x = 1 \\ therefore \: a \: possibe \: solution \: is \: (18,-10).

Hope this helped you!

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