Solve the given pair of linear equations and find the value of x and z:
\sf{\longrightarrow\:\dfrac{4}{16x+24z}+\dfrac{12}{21x-14z}=\dfrac{1}{2}}⟶
16x+24z
4
+
21x−14z
12
=
2
1
and
\sf{\longrightarrow\:\dfrac{14}{4z+6z}+\dfrac{4}{3x-2z}=2}⟶
4z+6z
14
+
3x−2z
4
=2
Please provide well-explained answers
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but u have to wait for 1 hour
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hlo ha aaj 11:15 ko live aana USI live pr
Nahi abhi tk Nahi Kiya dinner XD
Tumne Kiya kya
btw iska answer kya
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