Solve the given pair of linear equations and find the value of x and z: \sf{\longrightarrow\:\dfrac{4}{16x+24z}+\dfrac{12}{21x-14z}=\dfrac{1}{2}}⟶16x+24z4+21x−14z12=21 and \sf{\longrightarrow\:\dfrac{14}{4z+6z}+\dfrac{4}{3x-2z}=2}⟶4z+6z14+3x−2z4=2 Please provide well-explained answers : )
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