Math, asked by Anonymous, 1 month ago

Solve the given pair of linear equations and find the value of x and z:

\sf{\longrightarrow\:\dfrac{4}{16x+24z}+\dfrac{12}{21x-14z}=\dfrac{1}{2}}


and


\sf{\longrightarrow\:\dfrac{14}{4z+6z}+\dfrac{4}{3x-2z}=2}

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Answers

Answered by chpravallika
2

Answer:

Solve the given pair of linear equations and find the value of x and z:

\sf{\longrightarrow\:\dfrac{4}{16x+24z}+\dfrac{12}{21x-14z}=\dfrac{1}{2}}⟶

16x+24z

4

+

21x−14z

12

=

2

1

and

\sf{\longrightarrow\:\dfrac{14}{4z+6z}+\dfrac{4}{3x-2z}=2}⟶

4z+6z

14

+

3x−2z

4

=2

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