Question

Solve the given pair of linear equations and find the value of x and z:
\sf{\longrightarrow\:\dfrac{4}{16x+24z}+\dfrac{12}{21x-14z}=\dfrac{1}{2}}⟶ \ \textless \ br /\ \textgreater \ 16x+24z\ \textless \ br /\ \textgreater \ 4⟶16x+24z4​+21x−14z12​=21​⟶ \textless br/ \textgreater 16x+24z \textless br/ \textgreater 4
​
+
21x−14z
12
​
=
2
1
​

and
\sf{\longrightarrow\:\dfrac{14}{4z+6z}+\dfrac{4}{3x-2z}=2}⟶ \ \textless \ br /\ \textgreater \ 4z+6z\ \textless \ br /\ \textgreater \ 14​ \ \textless \ br /\ \textgreater \ + \ \textless \ br /\ \textgreater \ 3x−2z\ \textless \ br /\ \textgreater \ 4\ \textless \ br /\ \textgreater \ ​=2⟶4z+6z14​+3x−2z4​=2⟶ \textless br/ \textgreater 4z+6z \textless br/ \textgreater 14​ \textless br/ \textgreater + \textless br/ \textgreater 3x−2z \textless br/ \textgreater 4 \textless br/ \textgreater ​=2
_______________________________​

Answer 1

Answer:

Thanks

Step-by-step explanation:

Types of Motion

Rectilinear motion,

Circular motion,

Periodic motion and.

Rotational motion.

Answer 2

Answer:

Q4.If the coordinates of a point are ( 0 , -5 ), then it lies in: * 1 point Positive direction of X-axis Positive direction of Y-axis Negative direction of Y- axis Negative direction of X- axis