Question

Solve the given pair of linear equations and find the value of x and z:

$\sf{\longrightarrow\:\dfrac{4}{16x+24z}+\dfrac{12}{21x-14z}=\dfrac{1}{2}}$

and

$\sf{\longrightarrow\:\dfrac{14}{4z+6z}+\dfrac{4}{3x-2z}=2}$


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Answer 1

Answer:

lve the given pair of linear equations and find the value of x and z:

$\sf{\longrightarrow\:\dfrac{4}{16x+24z}+\dfrac{12}{21x-14z}=\dfrac{1}{2}}$

and

$\sf{\longrightarrow\:\dfrac{14}{4z+6z}+\dfrac{4}{3x-2z}=2}$

Explanation:

degree of divisor is always greater than the degree of remainderlve the given pair of linear equations and find thlve the given pair of linear equations and find the value of x and z:

$\sf{\longrightarrow\:\dfrac{4}{16x+24z}+\dfrac{12}{21x-14z}=\dfrac{1}{2}}$

and

$\sf{\longrightarrow\:\dfrac{14}{4z+6z}+\dfrac{4}{3x-2z}=2}$e value of x and z:

$\sf{\longrightarrow\:\dfrac{4}{16x+24z}+\dfrac{12}{21x-14z}=\dfrac{1}{2}}$

and

$\sf{\longrightarrow\:\dfrac{14}{4z+6z}+\dfrac{4}{3x-2z}=2}$

Answer 2

Answer:

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