Question

Solve the given problem.


Irrelevant answers will be reported.​

Answer 1

$28.44 \: cm$

Step-by-step explanation:

$Given, \: \: \: hemishpere \: \: of \: \: radius \: (r) = 8 \: cm \: \: \: and \\ right \: \: circular \: \: cone \: \: of \: \: bass \: \: radius \: (r_{o} ) = 6 \: cm \\ Let, \: \: heigth = h \\ A/Q, \: \: \boxed{volume \: \: of \: \: hemisphere = volume \: \: of \: \: cone} \\ \frac{2}{3}\pi {r}^{3} = \frac{1}{3} \pi {r_{o}}^{2}h \\ putting \: \: values \\ \frac{2}{3} \pi \times (8)^{3} = \frac{1}{3}\pi \times ({6})^{2} \times h \\ 2 \times {8}^{3} = {6}^{2} \times h \\ 2 \times 512 = 36 \times h \\ 1024 = 36h \\ h = \frac{1024}{36} \\ h = 28.44 \: cm$