Question

Solve the given problems applying the Polya’s 4 steps in showing the solutions.

1. The length of a rectangle is four less than three times its width. If the perimeter of the rectangle is 8 meters, what re the dimensions of the rectangle
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Answer 1

Step-by-step explanation:

Width = W cm

Length = 3W-4 cm

Perimeter (double the sum of length + width) = 2W + 6W-8 cm (88 cm)

8W- 8 - 88 = 0

8W-96 = 0

8W=96.

W= 96/8

W = 12 cm

L = 3W-4, = 3x12 - 4 L = 32

If L = 32, W = 12, perimeter (as a check) = 2(32+12), or 88.

Answer 2

Thanks for your question...

Your required answer :

Given :

• The length of a rectangle is four less than three times its width.
• Perimeter = 8 m

To find :

• Length and Breadth

Equation formed :

• Breadth = x
• Length = 3x - 4

Solution :

• 2 ( x + 3x - 4 ) = 8
• 2 ( 4x - 4 ) = 8
• 4x - 4 = 4
• 4 ( x - 1 ) = 4
• x - 1 = 1
• x = 2

Now ,

• Breadth = 2 metre

• Length :
• 2 ( l + 2 ) = 8
• l + 2 = 4
• l = 2 m