Question

Solve the given puzzle using the equation-Sahil has Rs.12 less than three times what Sohan has. If both have a total of Rs.88, how many rupees each must have got?

Answer 1

SOLUTION :

Let the amount of money Sohan has = ₹ x

Amount of money with Sahil = ₹(3x -12)

Total amount of money with Sohan and Sahil =₹ [ x +(3x - 12) ] = 4x - 12

Given : Total amount of money with Sohan and Sahil = ₹ 88

88 = 4x - 12

88 +12 = 4x

100 = 4x

x = 100/4 = 25

Amount of money Sohan has= ₹ 25

Amount of money with Sahil = ₹(3x -12) = ₹ (3 × 25 -12) = ₹ (75 - 12) = ₹ 63

Amount of money with Sahil = ₹ 63

Hence, Sohan had ₹ 25 and Sahil has ₹ 63.

HOPE THIS ANSWER WILL HELP YOU..

Answer 2

Hi ,

Let Sohan money = Rs x

Sahil has Rs 12 less than three

times what Sohan has .

Sahil money = 3x - 12

Total money = 88

( Sohan money + Sahil money ) = 88

x + ( 3x - 12 ) = 88

4x - 12 = 88

4x = 88 + 12

4x = 100

x = 100/4

x = 25

Therefore ,

Sohan money = x = Rs 25

Sahil money = ( 3x - 12 )

= 3 × 25 - 12

= 75 - 12

= Rs 63

I hope this helps you.

: )