Solve the given puzzle using the equation-Sahil has Rs.12 less than three times what Sohan has. If both have a total of Rs.88, how many rupees each must have got?
Answers
SOLUTION :
Let the amount of money Sohan has = ₹ x
Amount of money with Sahil = ₹(3x -12)
Total amount of money with Sohan and Sahil =₹ [ x +(3x - 12) ] = 4x - 12
Given : Total amount of money with Sohan and Sahil = ₹ 88
88 = 4x - 12
88 +12 = 4x
100 = 4x
x = 100/4 = 25
Amount of money Sohan has= ₹ 25
Amount of money with Sahil = ₹(3x -12) = ₹ (3 × 25 -12) = ₹ (75 - 12) = ₹ 63
Amount of money with Sahil = ₹ 63
Hence, Sohan had ₹ 25 and Sahil has ₹ 63.
HOPE THIS ANSWER WILL HELP YOU..
Hi ,
Let Sohan money = Rs x
Sahil has Rs 12 less than three
times what Sohan has .
Sahil money = 3x - 12
Total money = 88
( Sohan money + Sahil money ) = 88
x + ( 3x - 12 ) = 88
4x - 12 = 88
4x = 88 + 12
4x = 100
x = 100/4
x = 25
Therefore ,
Sohan money = x = Rs 25
Sahil money = ( 3x - 12 )
= 3 × 25 - 12
= 75 - 12
= Rs 63
I hope this helps you.
: )