Question

Solve the given puzzle using the equation-The present age of Beena is 2 years more than Reeta. The present age of Teena is 3 years more than Beena. If the sum of the ages of Reeta, Beena, and Teena is 79 years, find the present age of all the three of them.

Answer 1

let Reeta's age be x

age of Beena = 2+x

age of Teena = 5+x

sum of their ages = 79

5+x+2+x+x = 79

7+3x=79

3x=79-7

3x=72

x=72/3

x=24

Age of Reeta= x=24

age of Beena = 2+x=2+24=26

age of Teena = 5+x=5+24=29

Answer 2

let the age of benna is x years
now teena's age is 3+x
reeta's age is x-2
then the age all of them is
x+(3+x)+(x-2)=79
3x+1=79
3x=78
x=26
the age of beena is 26 years
" " " reeta " (26-2)
=24 years
" " " teena " (26+3)
29 years