Question

Solve the given quadratic equation:
2x² + 3ix + 2 =0

Answer 1

Answer:

x = i(-3±5)/4

Step-by-step explanation:

2x^2 + 3ix + 2 = 0

Using quadratic equation;

we know, x = (-b ± √b^2 - 4ac)/2

x =  [-3i ± √(3i)^2 - 4x2x2]/2x2

= -3i ± √-25/4

= i(-3±5)/4

Answer 2

To solve this equation, let us apply Quadratic formula

$2{x}^{2} +3ix + 2= 0 \\ \\ a = 2\\ \\ b = 3i \\ \\ c = 2 \\ \\ x_{1,2} = \frac{ - b ± \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_{1,2} = \frac{ -3i ± \sqrt{ {(-3i)}^{2} - 4(2)(2)} }{2 \times 2} \\ \\ x_{1,2} = \frac{ -3i ± \sqrt{-9 - 16} }{4} \\ \\ x_{1,2} = \frac{ -3i±\sqrt{ -25} }{4} \\ \\ \\ x_{1,2} = \frac{ -3i± 5i}{4} \\ \\ x_{1} = \frac{-3i+5i}{4} \\ \\x_{1} =\frac{i}{2}\\\\ x_{2} = \frac{ -3i-5i}{4} \\ \\x_{2} =-2i$
Hope it helps you.