Solve the given quadratic equation (x2+1)2-x2=0 has
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Answer:
x= -1 +3i /2 , -1 -3i/2
Step-by-step explanation:
(x^2+1)^2-x^2=0
x^4 + 1 + 2x^2 - x^2 =0
x^4 +1 + x^2 =0
where a= 1, b=1 ,c=1
Now , by determinant method :
D= b^2-4*a*c = 1 - 4*1*1= 1-4 = -3< 0
Thus , no real root exists
x = -1 + √-3 / 2 ,-1 - √-3 /2
x = -1 +3i /2 , -1 -3i/2 where i =√-1
Hope it helps you!
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