Question

Solve the given quadratic equation (x2+1)2-x2=0 has

Answer 1

Answer:

x= -1 +3i /2 , -1 -3i/2

Step-by-step explanation:

(x^2+1)^2-x^2=0

x^4 + 1 + 2x^2 - x^2 =0

x^4 +1 + x^2 =0

where a= 1, b=1 ,c=1

Now , by determinant method :

D= b^2-4*a*c = 1 - 4*1*1= 1-4 = -3< 0

Thus , no real root exists

x = -1 + √-3 / 2 ,-1 - √-3 /2

x = -1 +3i /2 , -1 -3i/2 where i =√-1

Hope it helps you!

Mark me as the Brainliest!!!!!