Solve the given quadratic equation:
x² - (3√2 + 2i)x + 6√2i = 0
Answers
Answered by
52
Answer:
Step-by-step explanation:
Since the given quadratic equation is easily factorizable over set of complex numbers, we may use factorization method to solve it.
x² - (3√2 + 2i)x + 6√2i = 0
(x - 3√2) (x - 2i) = 0
x = 3√2, 2i
The required roots are
3√2, 2i
Answered by
56
Solution :
Given Quadratic equation ,
x² - (3√2 + 2i)x + 6√2i = 0
=> x² - 3√2x - 2ix + (3√2)(√2i) = 0
=> x( x - 3√2 ) - 2i( x - 3√2 ) = 0
=> ( x - 3√2 )( x - 2i ) = 0
=> x - 3√2 = 0 or x - 2i = 0
.
=> x = 3√2 or x = 2i
Therefore ,
3√2 , 2i are roots of given quadratic
equation.
•••••
Given Quadratic equation ,
x² - (3√2 + 2i)x + 6√2i = 0
=> x² - 3√2x - 2ix + (3√2)(√2i) = 0
=> x( x - 3√2 ) - 2i( x - 3√2 ) = 0
=> ( x - 3√2 )( x - 2i ) = 0
=> x - 3√2 = 0 or x - 2i = 0
.
=> x = 3√2 or x = 2i
Therefore ,
3√2 , 2i are roots of given quadratic
equation.
•••••
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