Question

Solve the given quadratic equation:
x² - (3√2 + 2i)x + 6√2i = 0

Answer 1

Answer:

Step-by-step explanation:

Since the given quadratic equation is easily factorizable over set of complex numbers, we may use factorization method to solve it.

x² - (3√2 + 2i)x + 6√2i = 0

(x - 3√2) (x - 2i) = 0

x = 3√2, 2i

The required roots are

3√2, 2i

Answer 2

Solution :

Given Quadratic equation ,

x² - (3√2 + 2i)x + 6√2i = 0

=> x² - 3√2x - 2ix + (3√2)(√2i) = 0

=> x( x - 3√2 ) - 2i( x - 3√2 ) = 0

=> ( x - 3√2 )( x - 2i ) = 0

=> x - 3√2 = 0 or x - 2i = 0
.
=> x = 3√2 or x = 2i

Therefore ,

3√2 , 2i are roots of given quadratic

equation.

•••••