Question

✨ solve the given quadratics-

➡ 4x²+1=0​

Answer 1

By using the formula,

$a^2 + b^2$= ( a + b )( a - b )

$4x^2+1^2$= ( 4x+ 1)( 4x-1)

( 4x+ 1)( 4x-1)=0

( 4x+1)=0, (4x-1)=0

4x = 0 - 1, 4x = 0 + 1

4x = -1 , 4x = + 1

x = -1/4, x = +1/4

Answer 2

The answer of this question is x =-1/2