Question

solve the given question .​

Answer 1

Answer:

We have, 11 letters: {A, A, E, I, I, O, M, N, N, T, X};

Out of them there are 3 pairs: {A, A}, {I, I} and {N, N}.

So, # of distinct letters is 8: {A, E, I, I, O, M, N, N, T, X}

As pointed out, there are 3 different cases possible.

{abcd} - all 4 letters are distinct: C48=70C84=70;

{aabc} - two letters are alike and other two are distinct: C13∗C27=63C31∗C72=63 (C13C31 is a # of ways to choose which two letters will be alike from 3 pairs and C27C72 # of ways to choose other two distinct letters from 7 letters which are left);

{aabb} - two letters are alike and other two letters are also alike: C23=3C32=3 (C33C33 is a # of ways of choosing two pairs of alike letter from 3 such pairs);

Total=70+63+3=136.

Answer : A)136

Hope it helps you

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Answer 2

Answer:

a is the the correct Answer Mate