solve the given Question;-
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x^2 + 8x + 20
Discriminent = b^2 - 4ac
= (8)^2 - 4(1)(20)
= 64 - 80
= - 16
Discriminent is negative.
So, the given polynomial does not have any root.
Discriminent = b^2 - 4ac
= (8)^2 - 4(1)(20)
= 64 - 80
= - 16
Discriminent is negative.
So, the given polynomial does not have any root.
Answered by
2
a=1, b=8,c=20................................................. .............Value of the discriminant = b2 - 4 ac=(8)^2-4×1×20 =64-80=-16 . ...The value of thediscriminant is negative i.e less than zero.
Hence, the quadratic equation x2 +8x+20 has no real zeroes.
Hence, the quadratic equation x2 +8x+20 has no real zeroes.
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