Question

solve the given question
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Answer 1

$\Rightarrow y- (2y - \frac{ 5y - 1}{3} ) = \frac{y - 1}{3} + \frac{1}{2}$

$\Rightarrow y- ( \frac{6y - 5y - 1}{3} ) = \frac{2(y - 1) + 3}{6}$$\Rightarrow y- \frac{y - 1}{3} = \frac{2y - 2 + 3}{6}$

$\Rightarrow\frac{3y - y - 1}{3} = \frac{2y + 1 }{6}$

$\Rightarrow\frac{2y - 1}{3} = \frac{2y + 1}{6}$

$\Rightarrow\frac{4y - 2}{6} = \frac{2y + 1}{6}$

$\Rightarrow4y - 2 = 2y + 1$

$\Rightarrow4y - 2y = 2 + 1$

$\Rightarrow2y = 3$

$\Rightarrow \: y = \frac{3}{2}$