Question

solve the given question

Answer 1

Answer:

Explanation:

i.) diameter of zinc = 2.6 A

                = $2.6\times10^{-10} m$

radius $= \frac{2.6 \times 10^{-10} }{2}$

         $= 1.3 \times 10^{-10}$

        $= 130 \times 10^{-12}$

ii.) no. of Zn atoms present in 1.6 cm length

 $= \frac{1.6}{2.6 \times 10^{-10}\times10^{2} }$

$= 6.154 \times 10^{7}$