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Hey dear here is your answer!!!!!
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(i)angle ACB = 40 degrees (BC=BA, equal angles opp. to equal sides)
(ii)angle abc= 180-40=140 (sum of consecutive angles id 180 degrees)
(iii) angle adc= 140 degrees ( opp. angle to angle abc)
(iv)angle acd = 40 degrees ( AB||DC, alternative interior angles)
(v)angle CAD = 40 degrees ( AD=DC, angles opp. to equal sides are equal)
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v) 40 because diagonal of rhombus bisects vertex angle
since it is rhombus its all sides are equal
terefore triangle ACD is isoceles . its two opposite angles are eaual .
therefoe
iv ) 40 due to same reason as( iv)
i) 40
since sum of all angles of a triangle are 180. angle ADC is 180-80=100
iii) 100
since all opposite angles of rhombus are same .therefore angle ABC =100
ii) 100
since it is rhombus its all sides are equal
terefore triangle ACD is isoceles . its two opposite angles are eaual .
therefoe
iv ) 40 due to same reason as( iv)
i) 40
since sum of all angles of a triangle are 180. angle ADC is 180-80=100
iii) 100
since all opposite angles of rhombus are same .therefore angle ABC =100
ii) 100
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