Question

Solve the given question in image :​

Answer 1

$\huge\mathfrak{Solution}$

Given that ,

Moles of CO2 (n) = Mass of CO2 / Molar mass

= 8.8(g) / 44(g mol to the power -1)

= 0.2 mol

According to ideal gas equation,

PV = nRT

V = NRT / P

V = 0.(mol) * 0.083(barLK to the power -1) * 304.25(K) / 1 (bar)

V = 5.05 L

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Answer 2

Given that ,

Moles of CO2 (n) = Mass of CO2 / Molar mass

= 8.8(g) / 44(g mol to the power -1)

= 0.2 mol

According to ideal gas equation,

PV = nRT

V = NRT / P

V = 0.(mol) * 0.083(barLK to the power -1) * 304.25(K) / 1 (bar)

V = 5.05 L

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