Question

Solve the given question ⬆

Note :-

• Topic - Geometry
• No spam
• With step by step explaination
• No coping
• Kindly attach pictures of the triangle constructed
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Answer 1

This triαngle is αn isosceles triαngle.

Becαuse the both sides of the triαngle are equαl.

Now to see know the steps to construct the triαngle.

1.) Drαw α 6cm segment ‘seg QR’.

2.) Tαke α protαcter [ᴄᴏᴍᴩᴀꜱꜱ] αnd meαsure 5cm from the scαle αnd plαce the end of the protαcter.

5.) At point Q αnd drαw αn αrc αs shown in the αttαchment, αnd drαw αnother αrc by placing the protαcter on point R.

4.) Now, you cαn see the αrc's intersecting eαch other, so join the αrc's αnd then meαsure seg PQ αnd seg PR, if they αre 5cm then the constructed triαngle is correct. ✅

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Answer 2

(Refer to the above attachment for diagram of the required triangle.)

[Note: A rough diagram may help.]

Steps of construction:-

1. Make base QR of length 6 cm through a ruler.
2. Now, make two arcs (part of a circle) of radius 5 cm from point Q and R.
3. Let them intersect in a point P.
4. Now, join P with Q and R. Thus, △PQR is the required triangle.

By observation,

• △PQR is an isosceles triangle. That is, ∠Q ≅ ∠R.
• And, ∠Q = 53° (take a protractor and measure).

[53° × 2 + 74° = 180° – verified.]