Question

solve the given question please​

Answer 1

Answer:

Height of the pole is ( a + b ) / 4.

Explanation:

Let,

Initial velocity of the ball be u.

Height of the pole be H.

Total horizontal distance covered by the ball during its time of flight be R.

From the properties of projectile motion :

• Maximum Height = [ u^2 sin^2 A ] / 2g
• Horizontal Range = [ u^2 sin 2A ] / g

*Where u is the initial velocity, A is the angle made by the projectile on x-axis and g is the acceleration due to gravity.

Here,

= > Total horizontal range is a + b.

= > a + b = { u^2 sin ( 2 x 45° ) } / g { Multiplying both sides of 1 / 2 }

= > ( a + b ) / 2 = ( u^2 × 2sin45°.cos45° ) / ( 2g ) { Using sin2A = 2sinA.cosA }

= > [ ( a + b ) / 2 ] x 1 / [ 2 cos45° ] = ( u^2 sin45° ) / 2g

= > ( a + b ) / ( 2 x 2cos45° ) = ( u^2 sin45° ) / 2g

= > ( a + b ) / ( 4 cos45° ) x sin45° = ( u^2 sin^2 45° ) / 2g

= > ( a + b ) / 4 x 1 / ( sin45° / cos45° ) = u^2 sin^2 45 / 2g

= > ( a + b ) / 4 = ( u^2 sin^2 45° ) / 2g

= > ( a + b ) / 4 = Maximum height ( here, it's height of the pole )

Hence the height of the pole is ( a + b ) / 4.