Solve the given Questions Correctly.
1.an object is placed 9 cm from the concave lens of focal length 12 cm find the magnification, position of the image, nature of the image ?
2.an object of size 3 centimetres is placed at a distance of 18 cm away from the convex lens of radius of curvature R 1 is equal to 7 cm,R2= 13 cm then find the magnification, image distance, size of image ,position of image
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Answers
Answered by
21
1)ANSWER :-
NATURE of IMAGE IS VIRTUAL, ERECT AND
MAGNIFICATION (M=1.5)
M=P/Q (.°. V/U)
M=4/6
M=-3/2g
M=-1.5
2)ANSWER:-
Nature of Image is Virtual and Erect.
&
Size of the Image: Diminished.
M=V/U
M=3/18
(M=6)
Attachments:
Answered by
20
Answer:
1st question:
Applying Lens formula :
So , the image will be formed at 36/7 cm.
Since the object is placed before the focus, we will get a virtual, erect and diminished image.
2nd question:
We shall use Lens Maker's Formula :
Putting value of u = -18, n2 = 3/2 , n1 = 1 , r1 = +7 cm and r2 = -13 cm, we get:
1/v = 1/(0.0548)
=> v = 18.24 cm.
Anonymous:
Fabulous
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