Question

Solve the given simultaneous linear equation in two variables.

The sides of an equilateral triangle are (6x+3y)cm, (8x+9y-5)cm and (10x+12y-8) respectively. Find the length of each side.
[Hint. Take 6x+3=8x+9y-5 as the first equation & 8x+9y-5=10x+12y-8 as the second equation.]​

Answer 1

Answer:

PLS MARK ME AS BRAINLIST

let a=b=c are the sides of triangle

(6x+3y)=(8x+9y-5)

2x+6y=5 first equation

6x+3y=10x+12y-8

4x+8y=8 second equation

multiplying equation first with -2 and then add with equation second

We get -4y=-2

so,y=1/2

now putting the value of y in equation second

we get 4x+4=8

4x=4

X=1

6×1+3×1/2=15/2

so, each side of the triangle is 15/2 cm