Question

Solve the given sum of Maths​

Answer 1

Answer:

4

Step-by-step explanation:

          $4^{x-3}$ = $4^{x}$ - 252

    $4^{x}$ - $4^{x-3}$ = 252

$4^{x}$ - $4^{-3}$ × $4^{x}$ = 252

  $4^{x}$ - $\frac{1}{64}$ × $4^{x}$ = 252

        $\frac{63}{64}$ × $4^{x}$ = 252

                $4^{x}$= 256

       x $log_{4}$4 = $log_{4}$256

       x $log_{4}$4 = $log_{4}$$4^{4}$

       x $log_{4}$4 = 4 $log_{4}$$4$

                 x=4

Answer 2

Answer:

4^(x-3) = 4^x - 252

2^[2(x-3)] = 2^2x - 252

2^2x-6 = 2^2x - 252

2^2x/2^6 = 2^2x - 252

x = 4

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Step-by-step explanation: