Question

solve the given system of equations by elimination, substitution and graphically method....2x-7y+10=0 and 3x+2y-10=0​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:Correct option is

Correct option isA

Correct option isAx=−1,y=1

Correct option isAx=−1,y=1Let 3x−7y+10=0 --- (1)

Correct option isAx=−1,y=1Let 3x−7y+10=0 --- (1) and y−2x−3=0 --- (2)

Correct option isAx=−1,y=1Let 3x−7y+10=0 --- (1) and y−2x−3=0 --- (2)Multiplying equation (2) with 7 we get, 7y−14x−21=0 ----- equation (3)

Correct option isAx=−1,y=1Let 3x−7y+10=0 --- (1) and y−2x−3=0 --- (2)Multiplying equation (2) with 7 we get, 7y−14x−21=0 ----- equation (3)Adding equations 1 and 3, we get 11x=−11=>x=−1

Correct option isAx=−1,y=1Let 3x−7y+10=0 --- (1) and y−2x−3=0 --- (2)Multiplying equation (2) with 7 we get, 7y−14x−21=0 ----- equation (3)Adding equations 1 and 3, we get 11x=−11=>x=−1Substituting

Correct option isAx=−1,y=1Let 3x−7y+10=0 --- (1) and y−2x−3=0 --- (2)Multiplying equation (2) with 7 we get, 7y−14x−21=0 ----- equation (3)Adding equations 1 and 3, we get 11x=−11=>x=−1Substitutingx=−1 in the equation (2), we get y−2(−1)−3=0=>y=1

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