Question

Solve the graphs and send me plz plz

Answer 1

53.  case1:-   a = constant (let k) 
                       a = k
                     dv/dt = k
                      dv =kdt 
                     v = u + kt where u is constant but paticle is rest initially so, u = 0
hence, v =kt , e.g  vα t
again, v =kt 
          dx/dt = kt
         x = 1.2kt^2 hence, xαt²
so, the in case 1 is parabolic increasing 
case2:- a = -k
v = -kt 
x = -1/2kt^2 
hence, in case2 graph of x-t is parabolic decreasing .
so, option (1) is correct.

54. 
 case1:- v = kt ( straight line with +ve slope ) 
case2 :- v = -kt ( st line with -ve slope )
hence, grpah (1) is correct .

55. similarly here,
  case1:-   
v = kt
x = kt^2/2 hence, xαt^2
hence, graph of x-t is parabolic increasing 

case2:- v = -k
           x = -kt hence, xα(-t) 
hence, graph of x-t will be  straight line with -ve slope 
so, option (4) is correct.

56.
similarly here,
case1:- a = k
            v =kt 
case2:- a =o
            v = constant 
case3:- a = k
            v= kt 

hence, (1) graph will be possible