Math, asked by mishrah697, 8 months ago

solve the hcf of 3312 and 4661 by long divisions algorithm​

Answers

Answered by Anonymous
9

4661 = 3318×1+1343

3318 = 1343×2+632

1343 = 632×2+79

632 = 79×8+0

HCF = 79

I hope this helps you

Answered by subham02rs46
0

Answer:

1

Step-by-step explanation:

3312 )4661(1

3312

_____________

1349 ) 3312 ( 2

2698

______________

614 ) 1349 ( 2

1228

___________

121 ) 614 ( 5

605

_______________

09 ) 121 ( 13

117

_____________

4 ) 9 ( 2

8

____________

1 ) 4 ( 4

4

___________

0

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