Solve the homogeneous system of equations : 4x + 3y - z = 0, 3x + 4y + z = 0, x - y - 2z = 0, 5x + y - 4z = 0 using matrix (rank)
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Step-by-step explanation:
Given as 3x – y + 2z = 0
4x + 3y + 3z = 0
5x + 7y + 4z = 0
The equation can be written as
AX = 0
Then, |A| = 3(12 – 21) + 1(16 – 15) + 2(28 – 15)
|A| = – 27 + 1 + 26
|A| = 0
So, the system has infinite solutions
Suppose z = k
3x – y = – 2k
4x + 3y = – 3k
So, x = (-9k/13), y = (-k/13) and z = k
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