Math, asked by ajayverma0, 10 months ago

solve the image question ​

Attachments:

Answers

Answered by warylucknow
1

The sum of 2^{3^{2^{3}}}+[(2^{3})^{2}]^{3} is 1.14\times e^{1975}.

Step-by-step explanation:

Solve the expression as follows:

2^{3^{2^{3}}}+[(2^{3})^{2}]^{3}=2^{3^{8}}+[2^{3\times 2}]^{3}

                      =2^{6561}+2^{6\times 3}

                      =2^{6561}+2^{18}\\

                      =1.14\times e^{1975}

Thus, the sum of 2^{3^{2^{3}}}+[(2^{3})^{2}]^{3} is 1.14\times e^{1975}.

Similar questions