Solve the inequalities 2x−1/x−1>2 here 2x-1/x-1 is in whole mod
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Step-by-step explanation:
We have,
(2x - 1) / (x - 1) 2
⇒ [2x (x + 1) - 1 (x + 1)] / (x2- 1) 2
⇒ (2x2+ 2x - x - 1) 2 (x2- 1)
⇒ 2x2+ x - 1 2x2- 2
⇒ x - 1
∴ Solution set = [ x ∈ R; x - 1 ] = ( - 1 ,)
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