Question

Solve the inequalities in Exércises 1 to 6.
2 < 3x -4 <5​

Answer 1

$\sf{2 < 3x - 4 < 5}$

Transposing 4

$\implies\sf{2 + 4 < 3x < 5+ 4}$

$\implies\sf{6 < 3x < 9}$

Dividing both sides by 3

$\implies\sf{\dfrac{6}{3} < \dfrac{3x}{3} < \dfrac{9}{3}}$

$\implies\bf{2 < x < 3 \:\:or\:\: 3 > x > 2}$