Question

solve the inequalities. (x-4)(x+1)(x-2) > 0​

Answer 1

Step-by-step explanation:

Given, (x1)

2

(x+1)

3

(x4)<0

Since square of a number cannot be <0

This means, one of (x+1)

3

or (x4) is <0

Now, (x+1)

3

<0 and x−4>0 => x<−1 and x>4 --- (1)

OR (x+1)

3

>0 and x−4<0 => x>−1 and x<4 --- (2)

From solutions of both possibilities, −1<x<4