Question

Solve the inequality 3x-5<x+7, when x is a 1)Natural Number, 2)Whole Number, 3)Integer, 4)Real Number​

Answer 1

Answer:

We have 3x – 5 < x + 7

⇒ 3x < x + 12 (Adding 5 to both sides)

⇒ 2x < 12 (Subtracting x from both sides)

⇒ x < 6 (Dividing by 2 on both sides)

(i) Solution set is {1, 2, 3, 4, 5}

(ii) Solution set is {0, 1, 2, 3, 4, 5}

(iii) Solution set is {....– 3, – 2, –1, 0, 1, 2, 3, 4, 5}

(iv) Solution set is {x : x ∈ R and x < 6}

, i.e., any real number less than 6 .