Math, asked by mrzapp134, 4 months ago

Solve the inequality for real x: 1/5<2x-1< 3/4,x∈R

Answers

Answered by Anonymous
0

Answer

3

(2x−1)

4

(3x−2)

5

(2−x)

3

(2x−1)

20

5(3x−2)−4(2−x)

3

(2x−1)

20

15x−10−8+4x

3

(2x−1)

20

19x−18

⇒20(2x−1)≥3(19x−18)

⇒40x−20≥57x−54

⇒−20+54≥57x−40

⇒34≥17x

⇒2≥x

Thus, all real numbers x, which are less than or equal to 2, are the solution, of of the given inequality.

Hence, the solution set of the given inequality is (−∞,2]

Answered by mathdude500
0

Question :-

Solve the inequality, for x∈R

\bf \:\dfrac{1}{5}  &lt; 2x - 1 &lt; \dfrac{3}{4}

Solution :-

\bf \:\dfrac{1}{5}  &lt; 2x - 1 &lt; \dfrac{3}{4}

Adding 1 in each term, we get

\bf\implies \:\dfrac{1}{5}  + 1 &lt; 2x - 1  + 1&lt; \dfrac{3}{4}  + 1

\bf\implies \:\dfrac{6}{5}  &lt; 2x  &lt; \dfrac{7}{4}

Divide by 2 each term, we get

\bf\implies \:\dfrac{3}{5}  &lt; x &lt; \dfrac{7}{8}

\bf\implies \:x∈ (\dfrac{3}{5} , \dfrac{7}{8} )

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