Question

Solve the inequality for real x.
$\frac{(2x - 1)}{3} \geqslant \frac{(3x - 2)}{4} - \frac{(2 - x)}{5}$
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Answer 1

Answer:

$\frac{(2x - 1)}{3} \geqslant \frac{(3x - 2)}{4} - \frac{(2 - x)}{5} \\ \frac{(2x - 1)}{3} \geqslant \frac{15x - 10 - (8 - 4x)}{20 } \\ \frac{(2x - 1)}{3} \geqslant \frac{15x - 10 - 8 + 4x}{20 } \\ \frac{(2x - 1)}{3} \geqslant \frac{(19x - 18)}{20} \\ 20(2x - 1) \geqslant 3(19x - 18) \\ 40x - 20 \geqslant 57x - 54 \\ 54 - 20 \geqslant 57x - 40x \\ 34 \geqslant 17x \\ \frac{34}{17} \geqslant x \\ x \leqslant 2$

Answer 2

Answer:AnswerNumber of atoms in close packaging = 0.5 mol1 has 6.022×10 23 particlesSo thatNumber of close-packed particles=0.5×6.022×10 23 =3.011×10 23 Number of tetrahedral voids = 2 × number of atoms in close packagingPlug the values we getNumber of tetrahedral voids =2×3.011×10 23 =6.022×10 23 Number of octahedral voids = number of atoms in close packagingSo thatNumber of octahedral voids =3.011×10 23 Total number of voids = Tetrahedral void + octahedral void =6.022×10 23 +3.011×10 23 =9.03×10 23

Step-by-step explanation:

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