Question

solve the initial value problem, y'tanx=y+1 , y(2)=0.​

Answer 1

Answer:

Solve the initial value problems: (a) y + (tanx)y = sin 2x, y(0) = 1. (b) x2y + 2xy − x +1=0, ... 1 cosx so (1) becomes y cosx. + sinx cos2 x y = sin 2x cosx. ⇒ d dx ( y cosx) = 2 sinx. ⇒ y.