Math, asked by BrainlyWarrior, 1 year ago

Solve the Integral:


(2x/x^2 + 3x + 2)


Chapter => Integrals.

Answers

Answered by rohitkumargupta
11

HELLO DEAR,





GIVEN:- integral is {2x/(x² + 3x + 2)}.dx



\bold{\int \{2x/(x^2 + 2x + x + 2)\}.dx}


\bold{\int \{2x/(x + 2)(x + 1)\}.dx}


solving by partial fraction;


2x/(x + 2)(x + 1) = A/(x + 2) + B/(x + 1)


2x = A(x + 1) + B(x + 2)


2x = x(A + B) + (A + 2B)


on comparing both side like Power of cofficient of x,


A + B = 2-----(1) , A + 2B = 0------(2)


on solving we get,


B = -2 , A = 4



now, \bold{\int \{4/(x + 2) - 2/(x + 1)\}.dx}


\bold{\{4log|x + 2| - 2log|x + 1| + c.\}}


where, C is arbitrary constant.



I HOPE IT'S HELP YOU DEAR,

THANK


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Answered by LEGENDARYSUMIT01
0
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