Solve the
inversion method
24
following equations by
x + 2 ya
3
2x+3y
Answers
Answered by
6
Answer:
dp wali ldki kamaal chhe :)
Answered by
1
Answer:
Writing the equations in matrix form, we get
[
2
3
−1
−2
][
x
y
]=[
7
11
]
(i.e.,) AX=B⇒X=A
−1
B
where A=[
2
3
−1
−2
]; X=[
x
y
] and B=[
7
11
]
To find A
−1
:
A=[
2
3
−1
−2
]
[
A
]=[
2
3
−1
−2
]=−4+3=−1
=0
adjA=[
−2
−3
1
2
]
A
−1
=
[
A
]
1
(adjA)=
−1
1
[
−2
−3
1
2
]=[
2
3
−1
−2
]
X=A
−1
B⇒[
x
y
]=[
2
3
−1
−2
][
7
11
]
=[
14−11
21−22
]=[
3
−1
]
⇒x=3,y=−1
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