Question

solve the java expression x³+XYZ+Y³​

Answer 1

Answer:

Given :-

→ x + y + z = 15.

→ xy + yz + zx = 71.

→ xyz = 10.

➡ To find :-

→ x³ + y³ + z³ .

▶ Solution :-

Here

x + y + z = 15.

=> ( x + y + z )² = ( 15 )² .

=> x² + y² + z² +2 xy + yz + zx = 225.

=> x² + y² + z² + 2 × 71 = 225.

=> x² + y² + z² + 142 = 225.

=> x² + y² + z² = 225 - 142.

•°• x² + y²+ z² = 83.

Now Here

→ x³ + y³ + z³ - 3xyz = ( x + y + z )( x² + y² + z² - ( xy + yz + zx ) .

=> x³ + y³ + z³ - 3( 10 ) = ( 15 )( 83 - ( 71 ) ).

=> x³ + y³ + z³ - 30 = 15 × ( 83 - 71 ) .

=> x³ + y³ + z³ - 30 = 15 × 12.

=> x³ + y³ + z³ = 180 + 30 .

•°• x³ + y³ + z³ = 210.

Hope this helps you to gain Knowledge in Sums

Answer 2

$\textsf{\large Given Expression}$

    $x^3 + xyz+y^3$

$\textsf{\large Java Expression}$

    $\texttt{x * x * x + x * y * z + y * y * y;}$