solve the linear congruence 25x≡15(mod "49)"
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solve the linear congruence 25x≡15(mod "49)"
Congruences: (a) 25x ≡ 15 (mod 29) which divides 15, hence, there exists gcd (25,29) = 1 solution. Our next step is Observe : 3 О 17x ≡ 3 О 30 (mod 49) ⇒ 51x ≡ 90 (mod 49).
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