Question

solve the linear equation​

Answer 1

Answer:

Step-by-step explanation:

m-$\frac{m-1}{2}$ = 1-$\frac{m-2}{3}$

$\frac{2m-m-1}{2}$ = $\frac{3-m-2}{3}$

$\frac{m-1}{2}$=$\frac{1-m}{3}$

3m-3=2-2m

5m=5

m=1

Answer 2

Answer:

$\boxed{\red{\bf m = 1}}$

Step-by-step explanation:

$\sf m - \dfrac{m-1}{2} = 1-\dfrac{m-2}{3}$

Taking LCM,

$\sf \implies \dfrac{2m - m-1}{2} = \dfrac{3 - m-2}{3}$

$\sf \implies \dfrac{ m-1}{2} = \dfrac{1-m}{3}$

On cross-multiplying,

$\sf \implies 3(m-1)=2(1-m)$

$\sf \implies 3m - 3 = 2 - 2m$

$\sf \implies 3m+2m = 2+3$

$\sf \implies 5m = 5$

$\sf \implies m = \dfrac{5}{5}$

$\boxed{\bf \therefore m = 1}$

Hence, the value of m is 1.