Math, asked by sapnaarora7980, 9 months ago

solve the linear equation 2x+3y=7/3x+5y=8​

Answers

Answered by mathematicalcosmolog
0

Answer:

The given pair of equations is solved in the uploaded photo

Attachments:
Answered by Joon111
5

2x+3y= 7

2x+3y= 72x= 7-3y

2x+3y= 72x= 7-3yx= (7-3y)/2

2x+3y= 72x= 7-3yx= (7-3y)/23{(7-3y)/2}+5y= 8

2x+3y= 72x= 7-3yx= (7-3y)/23{(7-3y)/2}+5y= 8(21-9y)/2 + 5y= 8

2x+3y= 72x= 7-3yx= (7-3y)/23{(7-3y)/2}+5y= 8(21-9y)/2 + 5y= 8(21-9y+10y)/2= 8

2x+3y= 72x= 7-3yx= (7-3y)/23{(7-3y)/2}+5y= 8(21-9y)/2 + 5y= 8(21-9y+10y)/2= 8(21+6y)/2= 8

2x+3y= 72x= 7-3yx= (7-3y)/23{(7-3y)/2}+5y= 8(21-9y)/2 + 5y= 8(21-9y+10y)/2= 8(21+6y)/2= 821+y= 16

y= -5

2x+3(-5)= 7

2x+3(-5)= 72x-15= 7

2x+3(-5)= 72x-15= 72x= 22

x= 11

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