Question

solve the linear equation 3x-1/3= 2(x-1/2)+5 and verify your answer​

Answer 1

hope it helps you.

hope it helps you.

Answer 2

Answer:

On solving linear equation , we get value of $x$ as , $x = \frac{13}{3}$  . Since ,

LHS = RHS = $\frac{38}{3}$ hence , linear equation is verified .

Step-by-step explanation:

To solve and verify : given linear equation .

Given : $3x -\frac{1}{3} =2 (x -\frac{1}{2}) + 5$

Solution :

• Here, we will use the below following steps to find a solution using the transposition method:

1. We will Identify the variables and constants in the given equation.
2. Then we differentiate the equation as LHS and RHS.
3. We take constants at RHS leaving variable at LHS.  
4. Simplify the equation using arithmetic operation as required to find the value of $x$ .
5. Then the result will be the solution for the given linear equation. By using the transposition method. we get,

       $3x -\frac{1}{3} =2 (x -\frac{1}{2}) + 5 \\\\3x -\frac{1}{3} = 2x - 1 + 5 \\\\3x -2x = \frac{1}{3} - 1 + 5\\\\x = \frac{1}{3} - \frac{1\times 3}{3}+ \frac{5\times 3}{3} \\\\x = \frac{1 -3 + 15}{3} \\\\x = \frac{13}{3}$    

• Verifying equation by substituting the value of $x$ in LHS and RHS .
• LHS = $3x - \frac{1}{3}$

                  $= 3(\frac{13}{3} )- \frac{1}{3} \\\\= 13 - \frac{1}{3}\\\\= \frac{39- 1}{3}\\\\= \frac{38}{3}$

• RHS = $2 (x -\frac{1}{2}) + 5$

                $= 2 ( \frac{13}{3}- \frac{1}{2}) + 5 \\\\= 2 ( \frac{26 - 3}{6} ) + 5 \\\\= 2 ( \frac{23}{6} ) + 5\\\\= \frac{23}{3}+ 5 \\\\= \frac{23 + 15}{3} \\\\= \frac{38}{3}$  

  ∵ LHS = RHS , hence verified .