Question

solve the linear equation 7(y+3)-2(x+2=14 by the elimination method​

Answer 1

Step-by-step explanation:

Simplify given equations

7(y+3)−2(x+2)=14

or 7y−2x=−3

and 4(y−2)+3(x−3)=2

or 4y+3x=19

new set of equations is :

7y−2x=−3...(1)

4y+3x=19...(2)

Let us use the elimination method to solve the given system of equation.

Multiply (1) by 3 and (2) by 2. And add both the

equations.

Adding

29y=29⇒y=

29

29

=1

21y−6x=−98y+6x=38

Substitute the value of x in equation (1), we have

7(1)−2x=−3

x=5

Answer: x=5 and y=1

Answer 2

Answer:

it is very very very easy

Step-by-step explanation:

it is given.,7 (y+3)-2 (x+2)=14

=>7y+21-2x-4=14

=>7y-2x=14-21+4(we will take all the variables on left side and nubers or constants on right sides)

=>7y-2x=-3

7y-2x+3=0( if we move number to R.H.S then R.H.S will be 0)

so the answer will be

=>x=7y+3/2